is kaibun¶
ソースコード¶
1#include <string>
2using namespace std;
3
4bool is_kaibun(string &s) {
5 for (int i = 0; i < s.size()/2; ++i) {
6 if (s[i] != s[s.size()-i-1]) return false;
7 }
8 return true;
9}
仕様¶
Warning
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