is kaibun

ソースコード

1#include <string>
2using namespace std;
3
4bool is_kaibun(string &s) {
5  for (int i = 0; i < s.size()/2; ++i) {
6    if (s[i] != s[s.size()-i-1]) return false;
7  }
8  return true;
9}

仕様

Warning

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